(New page: == part A == <math>e^{st}\rightarrow h(t)\rightarrow H(S)e^{st}</math> <math>H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt</math>) |
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<math>H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt</math> | <math>H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt</math> | ||
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+ | assume | ||
+ | |||
+ | <math>h(t) = 5u(t-3)</math> |
Revision as of 18:28, 25 September 2008
part A
$ e^{st}\rightarrow h(t)\rightarrow H(S)e^{st} $
$ H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt $
assume
$ h(t) = 5u(t-3) $