| Line 4: | Line 4: | ||
<math>a_k = \frac{1}{N}\sum_{n=N} x[n]e^{-jkw_0n}</math> | <math>a_k = \frac{1}{N}\sum_{n=N} x[n]e^{-jkw_0n}</math> | ||
| + | |||
| + | assume that | ||
| + | |||
| + | x[0] = 0 | ||
| + | |||
| + | x[1] = 2 | ||
| + | |||
| + | x[2] = 0 | ||
| + | |||
| + | x[3] = 2 | ||
| + | |||
| + | x[4] = 0 | ||
| + | |||
| + | . | ||
| + | |||
| + | . | ||
| + | |||
| + | . | ||
| + | |||
| + | . | ||
| + | |||
| + | |||
| + | N = 4 | ||
| + | |||
| + | let's solve for coefficients | ||
| + | |||
| + | <math>w_0 = \frac{2\pi}{4}</math> | ||
| + | |||
| + | <math>a_0 = \frac{1}{4}\sum_{n=0}^{3} x[n]e^{-j0\pi n} | ||
| + | </math> | ||
Revision as of 17:46, 25 September 2008
Discrete time Fourier series
$ x[n] = \sum_{k=N} a_ke^{-jkw_0n} $
$ a_k = \frac{1}{N}\sum_{n=N} x[n]e^{-jkw_0n} $
assume that
x[0] = 0
x[1] = 2
x[2] = 0
x[3] = 2
x[4] = 0
.
.
.
.
N = 4
let's solve for coefficients
$ w_0 = \frac{2\pi}{4} $
$ a_0 = \frac{1}{4}\sum_{n=0}^{3} x[n]e^{-j0\pi n} $
