(CT Fourier Series)
(CT Fourier Series)
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If input is <math>(1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t)</math>
 
If input is <math>(1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t)</math>
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<math>= (1 + j)(\frac {e^{j \frac{\pi}{2}t + \pi j} + e^{-j \frac{\pi}{2}t - \pi j}}{2})(\frac{e^{j \frac{\pi}{4}t} - e^{-j \frac{\pi}{4}t}}{2j})</math>

Revision as of 08:48, 26 September 2008

CT Fourier Series

If input is $ (1 + j)cos(\frac{\pi}{2}t + \pi)sin(\frac{\pi}{4}t) $


$ = (1 + j)(\frac {e^{j \frac{\pi}{2}t + \pi j} + e^{-j \frac{\pi}{2}t - \pi j}}{2})(\frac{e^{j \frac{\pi}{4}t} - e^{-j \frac{\pi}{4}t}}{2j}) $

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