(h[n] and H(z))
Line 12: Line 12:
  
 
<math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup>
 
<math> \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z</math><sup>(<math>-m</math>)</sup>
<math> \,\ H[z] = \sum_{m=-6}^{5}
+
<math> \,\ H[z] = \sum_{m=-6}^{5}Z</math><sup>(<math>-m</math>)</sup>

Revision as of 15:18, 25 September 2008

Define a DT LTI System

$ \,\ x[n] = 5*u[n-5] + 6*u[n+6] $

h[n] and H(z)



We obtain $ h[n] $ by finding the response of $ x[n] $ to the unit impulse response ($ \delta[n] $).

$ \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] $

$ \,\ H[z] = \sum_{m=-\infty}^\infty h[m] * Z $($ -m $) $ \,\ H[z] = \sum_{m=-6}^{5}Z $($ -m $)

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