(New page: I began the same way as Beau with the drawing of a circle. Then i had drawn a chord from one side to the other. I then drew a line for the radius intersecting that chord so that the two ...) |
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− | I began the same way as Beau with the drawing of a circle. Then i had drawn a chord from one side to the other. I then drew a line for the radius intersecting | + | [[Image:hw5number3SA_ECE302Fall2008sanghavi.jpg]] |
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+ | I began the same way as Beau with the drawing of a circle. Then i had drawn a chord from one side to the other. I then drew a line for the radius to one end of the chorde. The distance D is the line intersecting the chord at a 90 degree angle. Then you can use Pythagorean thm to find the distance L. Then to find the PDF of the whole chord, i just used the formula with the integral and used the parameters or D and fx(x) as 2 times the L. |
Revision as of 12:40, 6 October 2008
I began the same way as Beau with the drawing of a circle. Then i had drawn a chord from one side to the other. I then drew a line for the radius to one end of the chorde. The distance D is the line intersecting the chord at a 90 degree angle. Then you can use Pythagorean thm to find the distance L. Then to find the PDF of the whole chord, i just used the formula with the integral and used the parameters or D and fx(x) as 2 times the L.