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== RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1 == | == RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1 == | ||
− | In question 1, I used the following signal: <math>f(t) = (3+j)cos(2t) + (10+j)sin(7t)\!</math> | + | In question 1, I used the following signal: |
− | + | <br> | |
+ | <math>f(t) = (3+j)cos(2t) + (10+j)sin(7t)\!</math> | ||
<br> | <br> | ||
+ | |||
From question 1, we also know that: | From question 1, we also know that: | ||
<br> | <br> | ||
<math>f(t) = ((3+j)\frac{e^{2jt}}{2} + (3+j)\frac{e^{-2jt}}{2} + (10+j)\frac{e^{7jt}}{2j} - (10+j)\frac{e^{-7jt}}{2j}\!</math> | <math>f(t) = ((3+j)\frac{e^{2jt}}{2} + (3+j)\frac{e^{-2jt}}{2} + (10+j)\frac{e^{7jt}}{2j} - (10+j)\frac{e^{-7jt}}{2j}\!</math> | ||
− | + | <br> | |
UNDER CONSTRUCTION | UNDER CONSTRUCTION |
Revision as of 11:37, 25 September 2008
Contents
CT LTI SYSTEM
I chose the following continusous-time linear time invariant system:
$ f(t) = \frac{7x(t)}{3} + \frac{9x(t+8)}{2}\! $
UNIT IMPULSE RESPONSE OF SYSTEM
To find the unit impulse response of the system, we set $ x(t) = \delta(t)\! $. Then we obtain the following unit impulse response:
$ h(t) = \frac{7\delta(t)}{3} + \frac{9\delta(t+8)}{2}\! $
THE SYSTEM FUNCTION
In order to compute the system function H(s), we can simply take the laplace transform of the unit impulse response of the system. When we take the laplace transform, we find that $ H(s) = \frac{7}{3} + \frac{9e^{-8jw}}{3}\! $
RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1
In question 1, I used the following signal:
$ f(t) = (3+j)cos(2t) + (10+j)sin(7t)\! $
From question 1, we also know that:
$ f(t) = ((3+j)\frac{e^{2jt}}{2} + (3+j)\frac{e^{-2jt}}{2} + (10+j)\frac{e^{7jt}}{2j} - (10+j)\frac{e^{-7jt}}{2j}\! $
UNDER CONSTRUCTION