(answer)
(Answer)
 
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==Hints==
 
1. This signal is the math equivalent of a synonym for the word 'strange'.
 
1. This signal is the math equivalent of a synonym for the word 'strange'.
  
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==answer==
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==Answer==
  
 
From 1, we know that the signal is odd... a sinewave is probably a safe guess.
 
From 1, we know that the signal is odd... a sinewave is probably a safe guess.
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From 2, we know that the signal is bounded by 0 and 8.. this means it has an amplitude of 4 and an offset of 4.
 
From 2, we know that the signal is bounded by 0 and 8.. this means it has an amplitude of 4 and an offset of 4.
  
From 3, we know that every a_k not equal to 0, -1, or 1 will be equal to 0... this verifies that it's a sinewave.
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From 3, we know that every a_k not equal to 0, -1, or 1 will be equal to 0... this verifies that it's a sinewave and real.
  
 
From 4, we know that the period is 5, making  <math>\omega=\frac{2\pi}{5}</math>
 
From 4, we know that the period is 5, making  <math>\omega=\frac{2\pi}{5}</math>
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Thus this signal is <math>4sin(\frac{2\pi}{5}t)+4</math>
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Thus this signal is....
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<math>x(t)=4sin(\frac{2\pi}{5}t)+4</math>

Latest revision as of 06:43, 25 September 2008

Hints

1. This signal is the math equivalent of a synonym for the word 'strange'.

2. This signal is never less than 0, but is always less than 8.

3. This signal's a_k is always 0 when it's greater than the absolute value of 1.

4. This signals period and the number of fingers on your hand share a common integer.


Answer

From 1, we know that the signal is odd... a sinewave is probably a safe guess.

From 2, we know that the signal is bounded by 0 and 8.. this means it has an amplitude of 4 and an offset of 4.

From 3, we know that every a_k not equal to 0, -1, or 1 will be equal to 0... this verifies that it's a sinewave and real.

From 4, we know that the period is 5, making $ \omega=\frac{2\pi}{5} $


Thus this signal is....

$ x(t)=4sin(\frac{2\pi}{5}t)+4 $

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Questions/answers with a recent ECE grad

Ryne Rayburn