(New page: ==Fourier Transform== Let <math>x(t)=sin(\pi t) + cos(2\pi t) </math> Remember that the formula for CT Fourier Series are: <math>x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t}</math> ...) |
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| + | <math>x(t)= \frac{e^{\pi jt}+e^{-\pi jt}}{2} + \frac{e^{2\pi jt}+e^{-2\pi jt}}{2}</math> | ||
Revision as of 05:14, 25 September 2008
Fourier Transform
Let $ x(t)=sin(\pi t) + cos(2\pi t) $
Remember that the formula for CT Fourier Series are:
$ x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t} $
$ a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt $.
Solution
$ x(t)= \frac{e^{\pi jt}+e^{-\pi jt}}{2} + \frac{e^{2\pi jt}+e^{-2\pi jt}}{2} $
