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3) <math> ak = 0 </math> for |k| > 1 | 3) <math> ak = 0 </math> for |k| > 1 | ||
| − | 4) <math> \frac{1}{2} \ | + | 4) <math> \frac{1}{2} \int_{0}^{2} |x(t)|^2 dt = 1 </math> |
Revision as of 16:20, 23 September 2008
"Guessing the Periodic Signal"
Supposing we are given a signal x(t)
1) x(t) is real and odd
2) x(t) is periodic with period T = 2 and has Fourier coefficients $ ak $
3) $ ak = 0 $ for |k| > 1
4) $ \frac{1}{2} \int_{0}^{2} |x(t)|^2 dt = 1 $
