| Line 8: | Line 8: | ||
<math> x(t) = cos(2* \pi * t) * cos(4* \pi * t) </math> | <math> x(t) = cos(2* \pi * t) * cos(4* \pi * t) </math> | ||
| − | <math> = \frac{e^{j*2*\pi*t} + e^ | + | <math> = \frac{e^{j*2*\pi*t} + e^{-j*2*\pi*t}}{2} </math> |
| + | |||
| + | <math> = \frac{1*e^{j*6*\pi*t}}{4} + \frac{e^{-j*2*\pi*t}}{4} </math> | ||
Revision as of 16:31, 23 September 2008
Define a Periodic CT signal and compute its Fourier series coefficients
Consider the following CT signal:
x(t) such that
$ x(t) = cos(2* \pi * t) * cos(4* \pi * t) $
$ = \frac{e^{j*2*\pi*t} + e^{-j*2*\pi*t}}{2} $
$ = \frac{1*e^{j*6*\pi*t}}{4} + \frac{e^{-j*2*\pi*t}}{4} $
