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| − | Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right. | + | Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right. - Wei Jian Chan |
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Revision as of 17:31, 15 September 2008
Comments
Instead of this method, we should expand it in terms of $ \cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\, $, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right. - Wei Jian Chan
