(New page: == Comments == Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal ...)
 
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== Comments ==
 
== Comments ==
Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right
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Instead of this method, we should expand it in terms of <math>\cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\,</math>, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right.
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Comment by : 00185-37978

Revision as of 17:30, 15 September 2008

Comments

Instead of this method, we should expand it in terms of $ \cos(2t) =\frac{e^{2jt}+e^{-2jt}}{2}\, $, as we what will happen to a random signal other than the signal shown. It might produce a different random response. By expanding it we can be sure it's right.

Comment by : 00185-37978

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010