| Line 3: | Line 3: | ||
'''Time Invariant Signal''' | '''Time Invariant Signal''' | ||
| + | |||
| + | <math>S_1(t) = 5x(t)</math> | ||
| + | |||
| + | <math>S_2(t) = t - t_0</math> | ||
| + | |||
| + | <math>x(t) -> S_1(t) -> S_2(t) -> 5x(t - t_0)</math> | ||
| + | |||
| + | <math>x(t) -> S_2(t) -> S_1(t) -> 5x(t - t_0)</math> | ||
| + | |||
| + | This means that <math>S_1(t) = 5x(t)</math> is a time invariant signal. | ||
| + | |||
| + | '''Time Variant Signal''' | ||
<math>S_1(t) = 5t</math> | <math>S_1(t) = 5t</math> | ||
Revision as of 16:14, 12 September 2008
A system is time invariant if for any time shifted input signal the system produces a shifted output such that if an input $ x(t) $ produced an output $ y(t) $ then the input $ x(t + t_0) $ would produced the output $ y(t + t_0) $
Time Invariant Signal
$ S_1(t) = 5x(t) $
$ S_2(t) = t - t_0 $
$ x(t) -> S_1(t) -> S_2(t) -> 5x(t - t_0) $
$ x(t) -> S_2(t) -> S_1(t) -> 5x(t - t_0) $
This means that $ S_1(t) = 5x(t) $ is a time invariant signal.
Time Variant Signal
$ S_1(t) = 5t $
$ S_2(t) = t - t_0 $
$ x(t) -> S_1(t) -> S_2(t) -> 5x(t - t_0) $
$ x(t) -> S_2(t) -> S_1(t) -> 5x(t - t_0) $
This means that $ S_1(t) = 5t $ is a time invariant signal.
