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However for <math>u[n]</math> we will need to cap off the <math>-\infty</math> to 0, since the for all values less then 0 the unit step would produce 0. | However for <math>u[n]</math> we will need to cap off the <math>-\infty</math> to 0, since the for all values less then 0 the unit step would produce 0. | ||
| − | + | X[n]=<math>\sum_{k=0}^{\infty}</math> δ[n-k]. | |
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| − | X[n]=<math>\sum_{k=0}^{\infty}</math> δ[n- | + | |
Latest revision as of 14:34, 12 September 2008
The system is defiantly not time invariant. When the signal is shifted the output is shifted also but a different magnitude is applied to the output, showing that time affects the output.
Sine we are talking about DT a setup of
$ X[n]=\sum_{k=-\infty}^{\infty} $ δ[n-k].
However for $ u[n] $ we will need to cap off the $ -\infty $ to 0, since the for all values less then 0 the unit step would produce 0.
X[n]=$ \sum_{k=0}^{\infty} $ δ[n-k].
