(New page: a) No, the function is not only shifted but the magnitude is scaled by some factor. b) u(n) since the equations are ... <math>Xk[n]=d[n-k], Yk[n]=(k+1)^2 d[n-(k+1)]</math>) |
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<math>Xk[n]=d[n-k], Yk[n]=(k+1)^2 d[n-(k+1)]</math> | <math>Xk[n]=d[n-k], Yk[n]=(k+1)^2 d[n-(k+1)]</math> | ||
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| + | to get u[n-1] as the output, k = 0 and d = u. | ||
Latest revision as of 07:47, 12 September 2008
a) No, the function is not only shifted but the magnitude is scaled by some factor.
b) u(n) since the equations are ...
$ Xk[n]=d[n-k], Yk[n]=(k+1)^2 d[n-(k+1)] $
to get u[n-1] as the output, k = 0 and d = u.
