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<math>x(t)\;=\;sin(\frac{3}{4}t)</math> | <math>x(t)\;=\;sin(\frac{3}{4}t)</math> | ||
| − | Sampling the signal at a frequency that is | + | Sampling the signal at a frequency that is a rational multiple of the frequency of the signal will result in a periodic DT signal. Sampling the signal at a frequency that is not a rational multiple of the frequency of the signal will result in a non-periodic DT signal. |
<math>2\pi f=\frac{3}{4}</math> | <math>2\pi f=\frac{3}{4}</math> | ||
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==Periodic DT Signal== | ==Periodic DT Signal== | ||
Sampling the signal at a frequency <math>f=\frac{3}{2\pi}</math> (four times the original frequency) yields a new frequency for the periodic DT signal <math>f_{DT}=\frac{1}{4}</math>, resulting in <math>x(t)=sin(\frac{1}{2}\pi t)</math>, which is clearly periodic (the repeating pattern: 0,1,0,-1,0,1,0). | Sampling the signal at a frequency <math>f=\frac{3}{2\pi}</math> (four times the original frequency) yields a new frequency for the periodic DT signal <math>f_{DT}=\frac{1}{4}</math>, resulting in <math>x(t)=sin(\frac{1}{2}\pi t)</math>, which is clearly periodic (the repeating pattern: 0,1,0,-1,0,1,0). | ||
| + | |||
| + | ==Non-Periodic DT Signal== | ||
| + | Sampling the signal at a frequency <math>f=\frac{3}{2\pi}</math> ( <math>8\pi</math> times the original frequency) yields a new frequency for the periodic DT signal <math>f_{DT}=\frac{1}{8\pi}</math>, resulting in <math>x(t)=sin(\frac{1}{4}t)</math>, which is clearly non-periodic (the repeating pattern: 0,1,0,-1,0,1,0). There is no integer multiple of frac{1}{f_{DT}}=8pi that is also an integer. | ||
Revision as of 12:46, 11 September 2008
Periodic CT Signal
In HW1, Kathleen Schremser posted the following periodic CT signal:
$ x(t)\;=\;sin(\frac{3}{4}t) $
Sampling the signal at a frequency that is a rational multiple of the frequency of the signal will result in a periodic DT signal. Sampling the signal at a frequency that is not a rational multiple of the frequency of the signal will result in a non-periodic DT signal.
$ 2\pi f=\frac{3}{4} $
$ f=\frac{3}{8\pi} $
Periodic DT Signal
Sampling the signal at a frequency $ f=\frac{3}{2\pi} $ (four times the original frequency) yields a new frequency for the periodic DT signal $ f_{DT}=\frac{1}{4} $, resulting in $ x(t)=sin(\frac{1}{2}\pi t) $, which is clearly periodic (the repeating pattern: 0,1,0,-1,0,1,0).
Non-Periodic DT Signal
Sampling the signal at a frequency $ f=\frac{3}{2\pi} $ ( $ 8\pi $ times the original frequency) yields a new frequency for the periodic DT signal $ f_{DT}=\frac{1}{8\pi} $, resulting in $ x(t)=sin(\frac{1}{4}t) $, which is clearly non-periodic (the repeating pattern: 0,1,0,-1,0,1,0). There is no integer multiple of frac{1}{f_{DT}}=8pi that is also an integer.
