(New page: before we start, ask yourself, how are you going to win a car. the answer is that there are two ways. Case 1. win by not swapping in this case you have to chose the car at fir...)
 
 
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case 2.  win by swapping
 
case 2.  win by swapping
           Think about it that after one goat door is open, the remaining doors contain a goat and a car and what behind your door can either be a goat or a car. Now in order to win by swapping, you have to have a goat behind your door (b/c if you have a car now, you will end up with a goat after swapping). so we can samplely calculate the possibility of getting goat in the first place, because after swapping you will end up with a car.
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           Think about it that after one goat door is open, the remaining doors contain a goat and a car and what behind your door can
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either be a goat or a car. Now in order to win by swapping, you have to have a goat behind your door (b/c if you have a car now,you'll end up with a goat after swapping). so we can samplely calculate the possibility of getting goat in the first place, because after swapping you will end up with a car.
 
           P(car after swap) = P(not a car in first pike) = P(goat) = 2/3
 
           P(car after swap) = P(not a car in first pike) = P(goat) = 2/3
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That's the youtube or orginal monte hall probelm solution, but '''doesn't apply to this 3.1B'''
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in this problem, two people are picking!
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case 1.  win by not swapping
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          in this case you have to chose

Latest revision as of 17:15, 16 September 2008

before we start, ask yourself, how are you going to win a car. the answer is that there are two ways.

Case 1. win by not swapping

         in this case you have to chose the car at first place and stick with it by now swapping. so the possibility will samplely 
         P(car) = 1/3

case 2. win by swapping

         Think about it that after one goat door is open, the remaining doors contain a goat and a car and what behind your door can
either be a goat or a car. Now in order to win by swapping, you have to have a goat behind your door (b/c if you have a car now,you'll end up with a goat after swapping). so we can samplely calculate the possibility of getting goat in the first place, because after swapping you will end up with a car.
         P(car after swap) = P(not a car in first pike) = P(goat) = 2/3

That's the youtube or orginal monte hall probelm solution, but doesn't apply to this 3.1B in this problem, two people are picking!

case 1. win by not swapping

         in this case you have to chose

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