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= The Inverse of a Matrix  =

<u></u> 

In linear algebra, the study of matrices is one of the fundamental basis of this subject. One of the concepts within this study, is the notion of an invertible or nonsingular matrix. 

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== Definition  ==

A square matrix is said to be '''invertible '''or '''nonsingular''', if when multiplied by another similar matrix, the result yields the identity matrix. 

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Let ''A'' and ''B'' be ''n × n'' matrices and ''I''<sub>''n''</sub> be the ''n × n'' identity matrix<br> 

A is invertible or nonsingular and B is its inverse if: 

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<math>\begin{align}
  & AB=BA={{I}_{n}} \\ 
 &  \\ 
 & \overbrace{\left( \begin{matrix}
   {{a}_{11}} & {{a}_{12}} & \cdots  & {{a}_{1n}}  \\
   {{a}_{21}} & {{a}_{22}} & \cdots  & {{a}_{2n}}  \\
   \vdots  & \vdots  & \ddots  & \vdots   \\
   {{a}_{n1}} & {{a}_{n2}} & \cdots  & {{a}_{nn}}  \\
\end{matrix} \right)}^{A}\overbrace{\left( \begin{matrix}
   {{b}_{11}} & {{b}_{12}} & \cdots  & {{b}_{1n}}  \\
   {{b}_{21}} & {{b}_{22}} & \cdots  & {{b}_{2n}}  \\
   \vdots  & \vdots  & \ddots  & \vdots   \\
   {{b}_{n1}} & {{b}_{n2}} & \cdots  & {{b}_{nn}}  \\
\end{matrix} \right)}^{B}=\overbrace{\left( \begin{matrix}
   1 & 0 & \cdots  & 0  \\
   0 & 1 & \cdots  & 0  \\
   \vdots  & \vdots  & \ddots  & \vdots   \\
   0 & 0 & \cdots  & 1  \\
\end{matrix} \right)}^{{{I}_{n}}} \\ 
\end{align}</math> 

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If the above condition is not met, and the determinant of matrix ''A'' is 0, then it is called '''singular '''or '''noninvertible'''. 

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If matrix ''B'' is matrix ''A'''s inverse, then it is written as ''A''<sup>-1</sup>. Matrix ''B'' is a unique matrix; there only exists one or no possible inverse of matrix ''A''. The proof of this notion is summarized below:<sup></sup>


<math>\begin{align}
  & \text{Let }B\text{ and }C\text{ be inverses of }A\text{. Then:} \\ 
 &  \\ 
 & AB=BA={{I}_{n}}\text{ and }AC=CA={{I}_{n}} \\ 
 &  \\ 
 & \text{Since any matrix multiplied by the identity matrix of the same dimension yields that same matrix, then:} \\ 
 &  \\ 
 & B=B{{I}_{n}}=B(AC)=(BA)C={{I}_{n}}C=C \\ 
 & \Rightarrow B=C\text{ and thus the inverse matrix, if it exists, is unique}\text{.} \\ 
\end{align}</math>




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