The easiest way to approach this problem is to simply list all the possible ways:

5 0 0

4 1 0

3 2 0

3 1 1

2 2 1


I didn't label the boxes because they are indistinguishable and therefore something like 2,2,1 is the same as 1,2,2. Counting them up I got an answer of 5 ways.

  • ysuo@purdue.edu
  • ysuo 18:17, 28 September 2008 (UTC)

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009