Yongseok Kim's Solution to 5.5 MA375Fall2008walther - Rhea

There are 5 possible groupings:

                               0 0 5 - 1
                               0 1 4 - 5
                               0 2 3 - 10
                               1 1 3 - 10
                               1 2 2 - 20

For a total of 46 possibilities. I don't see a more general formula for this. Because [A][B][C] and [B][A][C] are same, the boxes are indistinguishable that proves.

As a result, 5 orders to indicate 5 indistinguishable objects into 3 indistinguishable boxes.--Kim297 21:56, 6 October 2008 (UTC)

--- grader's comment : good job. I also got the same answer for the question!
-- by lee462 10:48, 5 October 2008 (UTC)