1 + 1 + 3
1 + 2 + 2
There are only two ways if for non-empty boxes,
5 + 0 + 0
4 + 1 + 0
3 + 2 + 0
There are 3 more ways if we consider empty boxes.
Total ways would be 5 if we consider empty boxes, else there are only 2 ways.
-Wooi-Chen Ng
