Causal

h[n] = h(t) = 0 , For all n < 0 & t < 0

  • Also, if output depends only on past OR present but NOT future values of "t" or "n".


Stable

$ \sum_{k=-\infty}^\infty |h[n]| < \infty $ , $ \int_{-\infty}^{\infty}|h(t)| < \infty. $


Memoryless

  • If output depends only on present values of "t" or "n".

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010