- Is this another collaborative challenge problem or would you prefer us to work on this alone?
Ah! I see how to do this now! Thank goodness for notes. I'll post the proof after class today. His Awesomeness, Josh Hunsberger
- Edit: got rid of the absolute values around the final two error estimates because those values would always be positive.
Okay, so I kinda messed up. Because the absolute value inside the integral means could be different than the absolute value outside the integral. But, again from class notes, the absolute value of an integral is always less than or equal to the integral of the absolute value of a function. So the result is the same, but I should not have made such large assumptions during the proof.His Awesomeness, Josh Hunsberger
