Search results for "Krwade" - Rhea

Create the page "Krwade" on this wiki! See also the search results found.

• 24
  ...he six men. so the final answer would be P(10,10)x P(11,6) --[[User:Krwade|Krwade]] 20:52, 4 February 2009 (UTC)
  2 KB (390 words) - 22:41, 4 February 2009
• Kim's Schedule
  my email is krwade@purdue.edu
  187 B (30 words) - 19:06, 27 January 2009
• 32
  ...en subtract that from the total ways with a which is 26^6. --[[User:Krwade|Krwade]] 21:11, 4 February 2009 (UTC)
  1 KB (193 words) - 22:45, 4 February 2009
• MA 375 Spring 2009 Walther Homework 4 Number 10
  ...and you multiply the three together...e and f are similar --[[User:Krwade|Krwade]] 21:33, 10 February 2009 (UTC)
  1 KB (198 words) - 20:40, 11 February 2009
• MA 375 Spring 2009 Walther Homework 5 Number 28
  ...e the C(80,11)? It just seems like that number is important--[[User:Krwade|Krwade]] 16:41, 17 February 2009 (UTC) I guess I still have the same question as Krwade. Where does the number C(80,11) come into play? It does seem like it will
  3 KB (433 words) - 19:51, 19 February 2009
• MA 375 Spring 2009 Walther Homework 5 Number 30
  ...be: <math>\frac{{6 \choose 5}(34)}{{40 \choose 6}}</math> --[[User:Krwade|Krwade]] 16:55, 17 February 2009 (UTC) ...ill be <math>\frac{{6 \choose 5}{34 \choose 1}}{{40 \choose 6}}</math>-- Krwade is right..
  2 KB (252 words) - 16:43, 18 February 2009
• MA 375 Spring 2009 Walther Homework 6 Number 30
  Does anyone understand part C. It's confusing me. --[[User:Krwade|Krwade]] 20:48, 24 February 2009 (UTC)
  629 B (91 words) - 16:23, 25 February 2009