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- a) <math class="inline">|e^2|= \sqrt{(e^2)^2}= e^2</math> ([[User:Clarkjv|Clarkjv]] 18:33, 10 January 2011 (UTC)) ...th class="inline">|e^{(2j)}| = \sqrt{(e^2)^2} = e^2</math> ([[User:Clarkjv|Clarkjv]] 18:33, 10 January 2011 (UTC))3 KB (397 words) - 15:17, 26 November 2013
- ([[User:Clarkjv|Clarkjv]] 22:34, 31 January 2011 (UTC)) <br>2 KB (380 words) - 09:20, 11 November 2011
- The sum appears to be computed correctly. ([[User:Clarkjv|Clarkjv]] 23:46, 31 January 2011 (UTC))1 KB (187 words) - 09:22, 11 November 2011
- ...h>(\sum_{k=-\infty}^n 5^{k})u[-n] = 5^{n+1}/4*u[-n] </math>([[User:Clarkjv|Clarkjv]] 23:35, 31 January 2011 (UTC))1 KB (255 words) - 09:22, 11 November 2011
- ...{n+3} - (1/5)^{\infty + 1})/(1-1/5) = 1/(4*5^{n+2})</math> ([[User:Clarkjv|Clarkjv]] 01:02, 3 February 2011 (UTC))1 KB (199 words) - 09:22, 11 November 2011
- ...nd not <span class="texhtml">''w''<sub>''o''</sub></span>? ([[User:Clarkjv|Clarkjv]] 20:36, 8 February 2011 (UTC)) </math> ([[User:Clarkjv|Clarkjv]] 11:38, 11 February 2011 (UTC))3 KB (548 words) - 09:24, 11 November 2011
- ...-j*k*\pi/2}/(2*\pi*j*k) = \frac{sin(k\pi/2)}{(k\pi)}</math>([[User:Clarkjv|Clarkjv]] 18:25, 8 February 2011 (UTC)) ([[User:Clarkjv|Clarkjv]] 18:25, 8 February 2011 (UTC))2 KB (264 words) - 09:25, 11 November 2011