This problem looks pretty easy considering what we learned from last chapter. Moreover if you prove problem 2 first it's trivial. (See Problem 2 : Finite Fields )
Since 3^6 = 729, 9=3^2 then from problem we know that [GF(729) : GF(9)] = [GF(3^6) : GF(3^2)] = 6/2 = 3
Since 2^6 = 64, 8=2^3 then from problem we know that [GF(64) : GF(8)] = [GF(2^6) : GF(2^3)] = 6/3 = 2
--Bakey 08:44, 30 November 2012 (UTC)
