I know we've done an example similar to this in class, but how do we start this problem?
Start with the probability of them not being on the same day which starts as 1*(6/7)*(5/7)*...*(1/7) for n<8. Then take 1 minus that to find the probability of them being born on the same day.--Spfeifer 16:01, 25 February 2009 (UTC)
For this problem, do we just assume that the probability of being born on each day of the week is equal? (Technically, since it states there are 366 days in the year...it would not come out this way, but parts b and c are hard to do otherwise.) - Karen
