P[s-E[s] = 400-E/s ;p>1/2] <= P[P[s-E[s] <= 400-E[s];p>1/2]

= P[|E[s]-s| >= E[s]-400;p>1/2]


P[|E[s]-s| >= E[s]-400;p>1/2] <= var[s]/(E[s]-400)^2 = f(p) <= max f(p) p>1/2

var[s] = 1000p(1-p)

Alumni Liaison

To all math majors: "Mathematics is a wonderfully rich subject."

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