To find cov(X,Y)

E[XY]=E[(Y+N)*Y]=E[Y^2]+E[Y]*E[N] (Y and N are independent)

E[Y^2]= var[Y]-(E[Y])^2= 0

E[XY]=0

cov(X,Y)=E[XY]-E[X]*E[Y]= - (1/lamda)^2

I solve cov(X,Y) in this way. Is it right ??

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang