Question
Supposing we are given a signal $ x(t) $
1) $ x(t) $ is real and odd
2) $ x(t) $ is periodic with period $ T = 5 $
3) $ a_{0}=0 $
4) peak to peak value of 3
Specify a signal that satisfies the given conditions.
Answer
$ signal=\frac{3}{2}sin(\frac{2\pi}{5}t) $
