The overall response for this system is

$ f(t) = tf(-t) $

To relate to the systems that were already use in example

$ \cos(2t) = \frac{e^{i2t}+e^{-i2t}}{2} $

So when the signal is run through the system the following is what is produced

$ \frac{e^{i2t}+e^{-i2t}}{2}=\frac{te^{-i2t}+te^{i2t}}{2} = t\frac{e^{-i2t}+e^{i2t}}{2} = t\cos(2t) $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn