As mentioned in the problem, the response of


$ e^{2jt}\, $

is

$ te^{-2jt}\, $


Suppose we let $ y(t) $ be the response of $ x(t) $, in order to make $ x(t) $ produce the output corresponding to $ y(t) $, we need to multiply the input by $ t $ and make the $ t $ of $ x $ negative. ie.


$ y(t) = tx(-t)\, $


This can be confirmed by the second condition, which is


$ te^{2jt}\, $


is the response of


$ e^{-2jt}\, $


Therefore, using the Euler formula:


$ cos(2t) = \frac{1}{2}(e^{-2jt}+e^{2jt})\, $


and the two responses mentioned above, the response of $ cos(2t) $ is:


$ \frac{1}{2}(te^{2jt}+te^{-2jt}) = tcos(2t)\, $

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett