So there are two cases 1.you pike first and 2.your friend pick first
case 1: you pike first
p(car)=1/3
case 2: your friend pike first
in order for you to get a car, your friend have to either pike goat#1 or goat#2.
your friend pike goat#1 and you pike a car
p(car case 1)=1/3*1/2
your friend pike goat#2 and you pike a car
P(car case 2)=1/3*1/2
in order to get the total possibility, you add the p(car case 1) and p(car case 2)together
we get P(car)=1/6+1/6=1/3
so i conclude the possibility is the same
