HW1, Chapter 0, Problem 24, MA453, Fall 2008, Prof. Walther
Problem Statement
Could somebody please state the problem?
Discussion
Let a1=a1 and a2a3...an=b1
If p is a prime and divides a1a2a3...an, then p divides a1b1
If p is a prime that divides a1b1, then p divides a1 or b1
Let's say p does not divide a1, then gcd(p,a1)=1
This means that there exists x and y for which the equation xp+ya1=1 holds
Let's multiply both sides of this equation by b1:
xpb1+ya1b1=b1
By induction, p divides a1b1 and let a1b1=kp. Let's divide the equation above by p:
xb1+yk=b1/p
If the LHS of the equation can be divided by p, the RHS of the equation can be divided by p also. Then, b1 can be divided by p.
Next, we let b2=a3a4...an and repeat the process above. Eventually, we will find the ai for some i, which can be divided by p.
-Ozgur