HW1.5 Justin Kietzman - Signal Energy and Power ECE301Fall2008mboutin - Rhea

Energy of a Signal

$ y = 3e^{t} $ from (0,5)

$ Energy = \int_{t1}^{t2} x(t) $

$ Energy = \int_{0}^{5}3e^{t}dt $

$ Energy = 3e^{5} - 3 $

Power of a Signal

$ y = 3e^{t} $ from (0,5)

$ Average Power = \frac{1}{t2 - t1}\int_{t1}^{t2}x(t)^2 $

$ Average Power = \frac{1}{5}\int_{0}^{5}3e^{2t}dt $

$ Average Power = \frac{1}{5}(\frac{3}{2}e^{10} - \frac{3}{2}) $

$ Average Power = \frac{3}{10}e^{10} - \frac{3}{10} $