ENERGY

$ E=\int_{t1}^{t2}{|f(t)|^2dt} $

$ E = \int_{0}^{2 \pi}{|2sin(t)|^2 dt} $

$ E=2\int_{0}^{2\pi}{|sin(t)|^2dt} $

$ E=(t-\frac{1}{2}sin(2t))|_{t=0}^{t=2\pi} $

$ \,\ E= 2 \pi $

POWER

$ P=\frac{1}{t_2 - t_1}\int_{t1}^{t2}{|f(x)|^2} $

$ P=\frac{1}{2{\pi} - 0}\int_{t1}^{t2}{|f(x)|^2} $

$ P=\frac{1}{2{\pi} - 0}*{2\pi} $

$ \,\ P= 1 $

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang