Problem 1
a1. by using integral over function square E = 6 so P = 0
a2. P = 6 / N so P is infinite
b. N must less than L + M - 1
c. 2*PI/T greater than 20000PI
so that T <= 1/10000
d. We did not cover the material
Problem 2
a. F(unit circle must be in ROCK)
b. T(summable)
c. T F(cause of the square root) T F
d. F(ak=a*-k) T(a-k = ak)
e. F
Problem 3:
a.m = K/A
b&c y(t) can be rewritten into 2 parts and has an energy of A^2/2 +k^2/32\t
