Solution to Q5 of Week 14 Quiz Pool
Since $ H(i,j)=\delta(i-1,j) $, the error calculated at the current value is reflected to the next value on the right as follows, $ \tilde{f}(i,j)=H(i,j)\ast e(i,j)+f(i,j)=e(i-1,j)+f(i,j) $
Thus, we can solve this discrete space system independently for each row of the input $ f(i,j) $.
And their corresponding outputs will be the same since each row of the input is equivalent.
Therefore the answers become simply,
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