Solution to Q1 of Week 11 Quiz Pool


The transfer function of the first and second systems are

$ H_1(z)=1-z^{-1}\,\! $
$ H_2(z)=\frac{1}{1-\frac{1}{2}z^{-1}} $

Then, the transfer function of the combined system, $ (T_1+T_2)[x[n]] $ is

$ \begin{align}H(z)=H_1(z)+H_2(z)&=1-z^{-1}+\frac{1}{1-\frac{1}{2}z^{-1}} \\ &=\frac{2-\frac{3}{2}z^{-1}+\frac{1}{2}z^{-2}}{1-\frac{1}{2}z^{-1}}\end{align} $

Thus, the impulse response $ h[n] $ of the combined system is (if we assume 'casual'),

$ h[n]=\delta[n]-\delta[n-1]+(0.5)^n u[n]\,\! $

And the difference equation for the combined system is

$ \begin{align}&H(z)=\frac{Y(z)}{X(z)}=\frac{2-\frac{3}{2}z^{-1}+\frac{1}{2}z^{-2}}{1-\frac{1}{2}z^{-1}} \\ &\Rightarrow Y(z)(1-\frac{1}{2}z^{-1})=X(z)(2-\frac{3}{2}z^{-1}+\frac{1}{2}z^{-2}) \\ &\Rightarrow y[n]-\frac{1}{2}y[n-1]=2x[n]-\frac{3}{2}x[n-1]+\frac{1}{2}x[n-2] \end{align} $



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Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva