Given that E and F are events such that P(E)=0.6 and P(F) = 0.3 and P(E and F) = 0.2 find P(E/F) and P(F/E)
solution:
P(E/F) = P(E and F)/P(F) = 0.2/0.3 = 2/3
P(F/E) = P(E and F)/P(E) = 0.2/0.6 = 1/3
Comments/questions/discussions
- Did you forget to put a link to your page on the assignment page?
- This would be a VERY easy exam problem. In a typical problem, you should expect to have to compute the probabilities for each event and for the intersection on your own, at the very least. -pm
