Dice Ho: fair Px|theta(X|theta 0) = 1/8 for all x
Dice H1: loaded Px|theta(X|theta1) = 1/4 if x =1,2
= 1/8 if x =3,4,5,6
my rule = R = {1, 2, 3}
Prob of type I = Pr[x E R|Ho) = 1/2
Prob of type II = Pr[x E R^2| H1) = 3/8
ML Rule for this:
Rml = {1, 2}
Type I = P[x E R|Ho] = 1/3
Type II = P[x E Rc|H1] = 1/2
