List the cyclic subgrous of U(30).
To do this, I listed each possible subgroup of U(30) and then tested whether they are cyclic. A problem I ran into, though, is that <13> appears to be cyclic and <23> does, but the answer in the back of the book does not include them.
Has anyone else encountered this problem or know the solution? I will try to ask during office hours....
--A. Cadwallader
I think they aren't in the back of the book because <13> is the same as <7> and <23> is the same as <17>.
--S. Rosenberger
Is <13> = <7> and <23> = 17 because they have the same elements or the same order. What I'm asking is if cyclic groups of the same order equal to each other.
--R. Kersey
They are equal because they describe the same set of elements, not because they have the same order.
- --Nick Rupley 12:55, 5 February 2009 (UTC)
--J. Korb
Just wondering if anyone found a better way of doing this problem than writing out all the subgroups and ignoring the ones that are the same. It seems like there should be a cleaner way of doing this.
