The multiplicative set of F of non-zero elements forms a group under multiplication. Since it has n-1 elements it means x^(n-1) = 1 (property of groups

-Sarah Liszka


Does this work? I was looking and don't we need the group to be cyclic for that to work?

-Allen Jarboe



Does anyone know how to do this one?


I don't completely understand this problem. Did somebody understand it well?

-Nate Shafer

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett