The way I interpret part b, we are looking for the probability that Landis doesn't catch a fish in 2 hours. It makes sense to me then that:

Pr[no fish in 2 hr] = 1-Pr[Fish in two hours or more]=1-UpperBound(Pr[Fish caught in two hours])

If my logic is correct, then the answer should just be a simple application of the Markov inequality.

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Ryne Rayburn