This is my little scratchpad for the variance.

$ Var(X) = E[(X-E[X])^2] $

$ Var(X) = E[(\sum_{i=1}^{n} X_i - \sum_{i=1}^{n}E[X_i])^2] $

$ = E[(\sum_{i=1}^{n} (X_i - E[X_i]))^2] $

Still working on it.

Alumni Liaison

Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010