This is my little scratchpad for the variance.

$ Var(X) = E[(X-E[X])^2] $

$ Var(X) = E[(\sum_{i=1}^{n} X_i - \sum_{i=1}^{n}E[X_i])^2] $

$ = E[(\sum_{i=1}^{n} (X_i - E[X_i]))^2] $

Still working on it.

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Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett