4.1a Eric Zarowny ECE302Fall2008sanghavi - Rhea

Here's what I did, and it seemed to work. Let me know if I forgot anything.

Simply expand the original $ Pr(x) = \left( \begin{array}{ccc} n \\ x \end{array} \right)p^{x}(1-p)^{n-x} $.

Now, see if substituting n-x for x and expanding results in the same answer.

Don't forget that: $ {n \choose k} = \frac{n \cdot (n-1) \cdots (n-k+1)} {k \cdot (k-1) \cdots 1} = \frac{n!}{k!(n-k)!} \quad \mbox{if}\ 0\leq k\leq n \qquad $

//comment Beau Morrison

Also remember to prove that:

$ {n \choose k} = {n \choose n-k} $

when solving the equality.