The equation of the system is

y(t)= t * x(-t)

the example in the problem tells us that $ e^2jt $ = t * $ e^-2jt $

and

$ e^-2jt $ = t * $ e^2jt $

Therefore, for x(t)=cos(2t)

we have,

   y(t)= t cos(-2t)
       = t cos(2t)    ( as we know that  cos(-t)= cos (t))

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett